Base | Representation |
---|---|
bin | 10100010111111111101… |
… | …001010111011001111111 |
3 | 11221212001002122120122120 |
4 | 110113333221113121333 |
5 | 140420003232430210 |
6 | 2551115510414023 |
7 | 203105051401056 |
oct | 24277751273177 |
9 | 4855032576576 |
10 | 1400153405055 |
11 | 49a890105829 |
12 | 1a7438661313 |
13 | a20596288b2 |
14 | 4baa6b3d39d |
15 | 2664b863270 |
hex | 145ffa5767f |
1400153405055 has 32 divisors (see below), whose sum is σ = 2279993253120. Its totient is φ = 733518965760.
The previous prime is 1400153404997. The next prime is 1400153405089. The reversal of 1400153405055 is 5505043510041.
It is not a de Polignac number, because 1400153405055 - 221 = 1400151307903 is a prime.
It is a super-2 number, since 2×14001534050552 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 518895 + ... + 1752015.
It is an arithmetic number, because the mean of its divisors is an integer number (71249789160).
Almost surely, 21400153405055 is an apocalyptic number.
1400153405055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1400153405055 is a deficient number, since it is larger than the sum of its proper divisors (879839848065).
1400153405055 is a wasteful number, since it uses less digits than its factorization.
1400153405055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1234471.
The product of its (nonzero) digits is 30000, while the sum is 33.
Adding to 1400153405055 its reverse (5505043510041), we get a palindrome (6905196915096).
The spelling of 1400153405055 in words is "one trillion, four hundred billion, one hundred fifty-three million, four hundred five thousand, fifty-five".
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