Base | Representation |
---|---|
bin | 1100101111000001100001… |
… | …1000000000001001100110 |
3 | 1211120120121121122212102211 |
4 | 3023300120120000021212 |
5 | 3313402100044031324 |
6 | 45440233035554034 |
7 | 2643416446026013 |
oct | 313603030001146 |
9 | 54516547585384 |
10 | 14002002330214 |
11 | 4509241313a48 |
12 | 16a18222bb91a |
13 | 7a74c9a35b22 |
14 | 3659b437270a |
15 | 194356ac1294 |
hex | cbc18600266 |
14002002330214 has 4 divisors (see below), whose sum is σ = 21003003495324. Its totient is φ = 7001001165106.
The previous prime is 14002002330119. The next prime is 14002002330229. The reversal of 14002002330214 is 41203320020041.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3500500582552 + ... + 3500500582555.
It is an arithmetic number, because the mean of its divisors is an integer number (5250750873831).
Almost surely, 214002002330214 is an apocalyptic number.
14002002330214 is a deficient number, since it is larger than the sum of its proper divisors (7001001165110).
14002002330214 is an equidigital number, since it uses as much as digits as its factorization.
14002002330214 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7001001165109.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 14002002330214 its reverse (41203320020041), we get a palindrome (55205322350255).
The spelling of 14002002330214 in words is "fourteen trillion, two billion, two million, three hundred thirty thousand, two hundred fourteen".
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