Base | Representation |
---|---|
bin | 1100101111000010010001… |
… | …1001110001100000101011 |
3 | 1211120121010200100220112111 |
4 | 3023300210121301200223 |
5 | 3313403003223334011 |
6 | 45440305045023151 |
7 | 2643424446152512 |
oct | 313604431614053 |
9 | 54517120326474 |
10 | 14002204121131 |
11 | 450933520a4a6 |
12 | 16a18799b4ab7 |
13 | 7a752c799335 |
14 | 3659d309d679 |
15 | 194369681121 |
hex | cbc2467182b |
14002204121131 has 2 divisors, whose sum is σ = 14002204121132. Its totient is φ = 14002204121130.
The previous prime is 14002204121123. The next prime is 14002204121203. The reversal of 14002204121131 is 13112140220041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14002204121131 - 23 = 14002204121123 is a prime.
It is a super-2 number, since 2×140022041211312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14002204124131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7001102060565 + 7001102060566.
It is an arithmetic number, because the mean of its divisors is an integer number (7001102060566).
Almost surely, 214002204121131 is an apocalyptic number.
14002204121131 is a deficient number, since it is larger than the sum of its proper divisors (1).
14002204121131 is an equidigital number, since it uses as much as digits as its factorization.
14002204121131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 14002204121131 its reverse (13112140220041), we get a palindrome (27114344341172).
The spelling of 14002204121131 in words is "fourteen trillion, two billion, two hundred four million, one hundred twenty-one thousand, one hundred thirty-one".
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