Base | Representation |
---|---|
bin | 1100101111000010011000… |
… | …0100001101000101011111 |
3 | 1211120121012121212101102200 |
4 | 3023300212010031011133 |
5 | 3313403032344140333 |
6 | 45440311523022543 |
7 | 2643425235254316 |
oct | 313604604150537 |
9 | 54517177771380 |
10 | 14002232021343 |
11 | 4509349a36325 |
12 | 16a188720aa53 |
13 | 7a75354b7637 |
14 | 3659d6a8327d |
15 | 19436bd42c13 |
hex | cbc2610d15f |
14002232021343 has 24 divisors (see below), whose sum is σ = 20452899714000. Its totient is φ = 9230235275520.
The previous prime is 14002232021299. The next prime is 14002232021359. The reversal of 14002232021343 is 34312023220041.
14002232021343 is a `hidden beast` number, since 1 + 400 + 2 + 2 + 3 + 2 + 0 + 213 + 43 = 666.
It is not a de Polignac number, because 14002232021343 - 212 = 14002232017247 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14002232021443) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 15923593 + ... + 16779906.
It is an arithmetic number, because the mean of its divisors is an integer number (852204154750).
Almost surely, 214002232021343 is an apocalyptic number.
14002232021343 is a deficient number, since it is larger than the sum of its proper divisors (6450667692657).
14002232021343 is a wasteful number, since it uses less digits than its factorization.
14002232021343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32704039 (or 32704036 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 14002232021343 its reverse (34312023220041), we get a palindrome (48314255241384).
The spelling of 14002232021343 in words is "fourteen trillion, two billion, two hundred thirty-two million, twenty-one thousand, three hundred forty-three".
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