Base | Representation |
---|---|
bin | 11111110101100110100111… |
… | …000110011111100011000011 |
3 | 200100210001220212121022201202 |
4 | 133311212213012133203003 |
5 | 121323114132233022201 |
6 | 1213445405405251415 |
7 | 41331221162522525 |
oct | 3765464706374303 |
9 | 610701825538652 |
10 | 140023032314051 |
11 | 40685486391737 |
12 | 1385549a263b6b |
13 | 60191663a4bb3 |
14 | 26812181cba15 |
15 | 112c4c1580c6b |
hex | 7f59a719f8c3 |
140023032314051 has 2 divisors, whose sum is σ = 140023032314052. Its totient is φ = 140023032314050.
The previous prime is 140023032314003. The next prime is 140023032314117. The reversal of 140023032314051 is 150413230320041.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-140023032314051 is a prime.
It is not a weakly prime, because it can be changed into another prime (140023032314251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70011516157025 + 70011516157026.
It is an arithmetic number, because the mean of its divisors is an integer number (70011516157026).
Almost surely, 2140023032314051 is an apocalyptic number.
140023032314051 is a deficient number, since it is larger than the sum of its proper divisors (1).
140023032314051 is an equidigital number, since it uses as much as digits as its factorization.
140023032314051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 140023032314051 its reverse (150413230320041), we get a palindrome (290436262634092).
The spelling of 140023032314051 in words is "one hundred forty trillion, twenty-three billion, thirty-two million, three hundred fourteen thousand, fifty-one".
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