Base | Representation |
---|---|
bin | 10100011000000100001… |
… | …111001111100000101011 |
3 | 11221212020110121111220200 |
4 | 110120010033033200223 |
5 | 140420132443134201 |
6 | 2551131301523243 |
7 | 203110005246456 |
oct | 24300417174053 |
9 | 4855213544820 |
10 | 1400230443051 |
11 | 49a91a6435a0 |
12 | 1a745a413523 |
13 | a206c58c9cb |
14 | 4bab307449d |
15 | 266534ce386 |
hex | 146043cf82b |
1400230443051 has 24 divisors (see below), whose sum is σ = 2207665662384. Its totient is φ = 848146844160.
The previous prime is 1400230443041. The next prime is 1400230443077. The reversal of 1400230443051 is 1503440320041.
It is a happy number.
1400230443051 is a `hidden beast` number, since 140 + 0 + 2 + 30 + 443 + 0 + 51 = 666.
It is not a de Polignac number, because 1400230443051 - 226 = 1400163334187 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1400230443041) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3803746 + ... + 4155591.
It is an arithmetic number, because the mean of its divisors is an integer number (91986069266).
Almost surely, 21400230443051 is an apocalyptic number.
1400230443051 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1400230443051 is a deficient number, since it is larger than the sum of its proper divisors (807435219333).
1400230443051 is a wasteful number, since it uses less digits than its factorization.
1400230443051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7961131 (or 7961128 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 27.
Adding to 1400230443051 its reverse (1503440320041), we get a palindrome (2903670763092).
The spelling of 1400230443051 in words is "one trillion, four hundred billion, two hundred thirty million, four hundred forty-three thousand, fifty-one".
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