Base | Representation |
---|---|
bin | 1000001001101000100… |
… | …0111111010111101011 |
3 | 111101102120202002021212 |
4 | 2002122020333113223 |
5 | 4243232400021301 |
6 | 144154313423335 |
7 | 13054643605556 |
oct | 2023210772753 |
9 | 441376662255 |
10 | 140025001451 |
11 | 544255100a5 |
12 | 2317a10ab4b |
13 | 10286b06a5a |
14 | 6ac4a9969d |
15 | 399800e4bb |
hex | 209a23f5eb |
140025001451 has 2 divisors, whose sum is σ = 140025001452. Its totient is φ = 140025001450.
The previous prime is 140025001433. The next prime is 140025001531. The reversal of 140025001451 is 154100520041.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-140025001451 is a prime.
It is not a weakly prime, because it can be changed into another prime (140025001421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70012500725 + 70012500726.
It is an arithmetic number, because the mean of its divisors is an integer number (70012500726).
Almost surely, 2140025001451 is an apocalyptic number.
140025001451 is a deficient number, since it is larger than the sum of its proper divisors (1).
140025001451 is an equidigital number, since it uses as much as digits as its factorization.
140025001451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 800, while the sum is 23.
Adding to 140025001451 its reverse (154100520041), we get a palindrome (294125521492).
The spelling of 140025001451 in words is "one hundred forty billion, twenty-five million, one thousand, four hundred fifty-one".
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