1400263941 has 4 divisors (see below), whose sum is σ = 1867018592. Its totient is φ = 933509292.

The previous prime is 1400263937. The next prime is 1400263951. The reversal of 1400263941 is 1493620041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1493620041 = 3 ⋅497873347.

It is not a de Polignac number, because 1400263941 - 2² = 1400263937 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1400263899 and 1400263908.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1400263901) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 233377321 + ... + 233377326.

It is an arithmetic number, because the mean of its divisors is an integer number (466754648).

Almost surely, 2^1400263941 is an apocalyptic number.

It is an amenable number.

1400263941 is a deficient number, since it is larger than the sum of its proper divisors (466754651).

1400263941 is an equidigital number, since it uses as much as digits as its factorization.

1400263941 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 466754650.

The product of its (nonzero) digits is 5184, while the sum is 30.

The square root of 1400263941 is about 37420.1007614891. The cubic root of 1400263941 is about 1118.7592395396.

Adding to 1400263941 its reverse (1493620041), we get a palindrome (2893883982).

The spelling of 1400263941 in words is "one billion, four hundred million, two hundred sixty-three thousand, nine hundred forty-one".