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140030540253 = 3249155756891
BaseRepresentation
bin1000001001101001111…
…0000111100111011101
3111101102222011111002200
42002122132013213131
54243240304242003
6144155032242113
713055041644642
oct2023236074735
9441388144080
10140030540253
115442865351a
122317bb40339
1310287cc5b56
146ac56dbdc9
1539987556a3
hex209a7879dd

140030540253 has 24 divisors (see below), whose sum is σ = 203045727456. Its totient is φ = 92994669600.

The previous prime is 140030540191. The next prime is 140030540317. The reversal of 140030540253 is 352045030041.

140030540253 is a `hidden beast` number, since 1 + 40 + 0 + 30 + 540 + 2 + 53 = 666.

It is not a de Polignac number, because 140030540253 - 212 = 140030536157 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140030540653) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2432938 + ... + 2489828.

It is an arithmetic number, because the mean of its divisors is an integer number (8460238644).

Almost surely, 2140030540253 is an apocalyptic number.

It is an amenable number.

140030540253 is a deficient number, since it is larger than the sum of its proper divisors (63015187203).

140030540253 is a wasteful number, since it uses less digits than its factorization.

140030540253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 57945 (or 57942 counting only the distinct ones).

The product of its (nonzero) digits is 7200, while the sum is 27.

Adding to 140030540253 its reverse (352045030041), we get a palindrome (492075570294).

The spelling of 140030540253 in words is "one hundred forty billion, thirty million, five hundred forty thousand, two hundred fifty-three".

Divisors: 1 3 9 491 557 1473 1671 4419 5013 56891 170673 273487 512019 820461 2461383 27933481 31688287 83800443 95064861 251401329 285194583 15558948917 46676846751 140030540253