14003300011 has 2 divisors, whose sum is σ = 14003300012. Its totient is φ = 14003300010.

The previous prime is 14003299997. The next prime is 14003300021. The reversal of 14003300011 is 11000330041.

14003300011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14003300011 - 2¹¹ = 14003297963 is a prime.

It is a super-2 number, since 2×14003300011² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14003299964 and 14003300000.

It is not a weakly prime, because it can be changed into another prime (14003300021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7001650005 + 7001650006.

It is an arithmetic number, because the mean of its divisors is an integer number (7001650006).

Almost surely, 2^14003300011 is an apocalyptic number.

14003300011 is a deficient number, since it is larger than the sum of its proper divisors (1).

14003300011 is an equidigital number, since it uses as much as digits as its factorization.

14003300011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 14003300011 its reverse (11000330041), we get a palindrome (25003630052).

The spelling of 14003300011 in words is "fourteen billion, three million, three hundred thousand, eleven".