Base | Representation |
---|---|
bin | 11111110101101111111111… |
… | …111101010001000011011001 |
3 | 200100211000221102012100012010 |
4 | 133311233333331101003121 |
5 | 121323300303412032301 |
6 | 1213454153553340133 |
7 | 41332026040125066 |
oct | 3765577775210331 |
9 | 610730842170163 |
10 | 140033113002201 |
11 | 406897896a7971 |
12 | 13857432267649 |
13 | 601a0b1a03a23 |
14 | 26818d2d55c6d |
15 | 112c8b157b5d6 |
hex | 7f5bfff510d9 |
140033113002201 has 32 divisors (see below), whose sum is σ = 199497359001600. Its totient is φ = 87159536601984.
The previous prime is 140033113002191. The next prime is 140033113002241. The reversal of 140033113002201 is 102200311330041.
It is not a de Polignac number, because 140033113002201 - 218 = 140033112740057 is a prime.
It is a super-3 number, since 3×1400331130022013 (a number of 43 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (140033113002241) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12015276 + ... + 20601773.
It is an arithmetic number, because the mean of its divisors is an integer number (6234292468800).
Almost surely, 2140033113002201 is an apocalyptic number.
It is an amenable number.
140033113002201 is a deficient number, since it is larger than the sum of its proper divisors (59464245999399).
140033113002201 is a wasteful number, since it uses less digits than its factorization.
140033113002201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32618565.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 140033113002201 its reverse (102200311330041), we get a palindrome (242233424332242).
The spelling of 140033113002201 in words is "one hundred forty trillion, thirty-three billion, one hundred thirteen million, two thousand, two hundred one".
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