Base | Representation |
---|---|
bin | 10100011000001010010… |
… | …011100010101010111001 |
3 | 11221212111120011000000122 |
4 | 110120022103202222321 |
5 | 140420340022432101 |
6 | 2551145335343025 |
7 | 203112352406363 |
oct | 24301223425271 |
9 | 4855446130018 |
10 | 1400332233401 |
11 | 49a972048152 |
12 | 1a7488521a75 |
13 | a20876ac39a |
14 | 4bac27add33 |
15 | 2665c3d951b |
hex | 1460a4e2ab9 |
1400332233401 has 2 divisors, whose sum is σ = 1400332233402. Its totient is φ = 1400332233400.
The previous prime is 1400332233319. The next prime is 1400332233439. The reversal of 1400332233401 is 1043322330041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1101450250000 + 298881983401 = 1049500^2 + 546701^2 .
It is an emirp because it is prime and its reverse (1043322330041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1400332233401 - 218 = 1400331971257 is a prime.
It is not a weakly prime, because it can be changed into another prime (1400332263401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700166116700 + 700166116701.
It is an arithmetic number, because the mean of its divisors is an integer number (700166116701).
Almost surely, 21400332233401 is an apocalyptic number.
It is an amenable number.
1400332233401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1400332233401 is an equidigital number, since it uses as much as digits as its factorization.
1400332233401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 1400332233401 its reverse (1043322330041), we get a palindrome (2443654563442).
The spelling of 1400332233401 in words is "one trillion, four hundred billion, three hundred thirty-two million, two hundred thirty-three thousand, four hundred one".
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