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140033304407 = 532642137819
BaseRepresentation
bin1000001001101010100…
…0101010011101010111
3111101110011100220210202
42002122220222131113
54243242011220112
6144155211411115
713055104306463
oct2023250523527
9441404326722
10140033304407
115442a171247
1223180a53a9b
1310288753049
146ac5c1b4a3
153998aee6c2
hex209aa2a757

140033304407 has 4 divisors (see below), whose sum is σ = 142675442280. Its totient is φ = 137391166536.

The previous prime is 140033304353. The next prime is 140033304431. The reversal of 140033304407 is 704403330041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140033304407 - 210 = 140033303383 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 140033304407.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140033304487) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1321068857 + ... + 1321068962.

It is an arithmetic number, because the mean of its divisors is an integer number (35668860570).

Almost surely, 2140033304407 is an apocalyptic number.

140033304407 is a deficient number, since it is larger than the sum of its proper divisors (2642137873).

140033304407 is an equidigital number, since it uses as much as digits as its factorization.

140033304407 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2642137872.

The product of its (nonzero) digits is 12096, while the sum is 29.

Adding to 140033304407 its reverse (704403330041), we get a palindrome (844436634448).

The spelling of 140033304407 in words is "one hundred forty billion, thirty-three million, three hundred four thousand, four hundred seven".

Divisors: 1 53 2642137819 140033304407