140033315122241 has 4 divisors (see below), whose sum is σ = 143817999314772. Its totient is φ = 136248630929712.

The previous prime is 140033315122159. The next prime is 140033315122243. The reversal of 140033315122241 is 142221513330041.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 60648333591616 + 79384981530625 = 7787704^2 + 8909825^2 .

It is a cyclic number.

It is not a de Polignac number, because 140033315122241 - 2⁴² = 135635268611137 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140033315122198 and 140033315122207.

It is not an unprimeable number, because it can be changed into a prime (140033315122243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1892342096210 + ... + 1892342096283.

It is an arithmetic number, because the mean of its divisors is an integer number (35954499828693).

Almost surely, 2^{140033315122241} is an apocalyptic number.

It is an amenable number.

140033315122241 is a deficient number, since it is larger than the sum of its proper divisors (3784684192531).

140033315122241 is an equidigital number, since it uses as much as digits as its factorization.

140033315122241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3784684192530.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 140033315122241 its reverse (142221513330041), we get a palindrome (282254828452282).

The spelling of 140033315122241 in words is "one hundred forty trillion, thirty-three billion, three hundred fifteen million, one hundred twenty-two thousand, two hundred forty-one".