Base | Representation |
---|---|
bin | 1100101111001001000000… |
… | …1110111001110110000110 |
3 | 1211120202210202111012022111 |
4 | 3023302100032321312012 |
5 | 3313420204340223024 |
6 | 45441204352051234 |
7 | 2643520334156161 |
oct | 313622016716606 |
9 | 54522722435274 |
10 | 14004013211014 |
11 | 450a083412502 |
12 | 16a20a3833b1a |
13 | 7a775a51c918 |
14 | 365b25460ad8 |
15 | 1944233d2a94 |
hex | cbc903b9d86 |
14004013211014 has 4 divisors (see below), whose sum is σ = 21006019816524. Its totient is φ = 7002006605506.
The previous prime is 14004013211009. The next prime is 14004013211029. The reversal of 14004013211014 is 41011231040041.
14004013211014 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×140040132110143 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3501003302752 + ... + 3501003302755.
It is an arithmetic number, because the mean of its divisors is an integer number (5251504954131).
Almost surely, 214004013211014 is an apocalyptic number.
14004013211014 is a deficient number, since it is larger than the sum of its proper divisors (7002006605510).
14004013211014 is an equidigital number, since it uses as much as digits as its factorization.
14004013211014 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7002006605509.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 14004013211014 its reverse (41011231040041), we get a palindrome (55015244251055).
The spelling of 14004013211014 in words is "fourteen trillion, four billion, thirteen million, two hundred eleven thousand, fourteen".
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