Base | Representation |
---|---|
bin | 11010000101011011… |
… | …00100010000011101 |
3 | 1100010222021011212220 |
4 | 31002231210100131 |
5 | 212140030040013 |
6 | 10233341215553 |
7 | 1004015152431 |
oct | 150255442035 |
9 | 40128234786 |
10 | 14004143133 |
11 | 5a36a79012 |
12 | 2869b615b9 |
13 | 142242c936 |
14 | 96bc749c1 |
15 | 56e6a0b23 |
hex | 342b6441d |
14004143133 has 4 divisors (see below), whose sum is σ = 18672190848. Its totient is φ = 9336095420.
The previous prime is 14004143129. The next prime is 14004143161. The reversal of 14004143133 is 33134140041.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14004143133 - 22 = 14004143129 is a prime.
It is a super-2 number, since 2×140041431332 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14004143033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2334023853 + ... + 2334023858.
It is an arithmetic number, because the mean of its divisors is an integer number (4668047712).
Almost surely, 214004143133 is an apocalyptic number.
It is an amenable number.
14004143133 is a deficient number, since it is larger than the sum of its proper divisors (4668047715).
14004143133 is an equidigital number, since it uses as much as digits as its factorization.
14004143133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4668047714.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 14004143133 its reverse (33134140041), we get a palindrome (47138283174).
The spelling of 14004143133 in words is "fourteen billion, four million, one hundred forty-three thousand, one hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.091 sec. • engine limits •