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14004143133 = 34668047711
BaseRepresentation
bin11010000101011011…
…00100010000011101
31100010222021011212220
431002231210100131
5212140030040013
610233341215553
71004015152431
oct150255442035
940128234786
1014004143133
115a36a79012
122869b615b9
13142242c936
1496bc749c1
1556e6a0b23
hex342b6441d

14004143133 has 4 divisors (see below), whose sum is σ = 18672190848. Its totient is φ = 9336095420.

The previous prime is 14004143129. The next prime is 14004143161. The reversal of 14004143133 is 33134140041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14004143133 - 22 = 14004143129 is a prime.

It is a super-2 number, since 2×140041431332 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14004143033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2334023853 + ... + 2334023858.

It is an arithmetic number, because the mean of its divisors is an integer number (4668047712).

Almost surely, 214004143133 is an apocalyptic number.

It is an amenable number.

14004143133 is a deficient number, since it is larger than the sum of its proper divisors (4668047715).

14004143133 is an equidigital number, since it uses as much as digits as its factorization.

14004143133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4668047714.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 14004143133 its reverse (33134140041), we get a palindrome (47138283174).

The spelling of 14004143133 in words is "fourteen billion, four million, one hundred forty-three thousand, one hundred thirty-three".

Divisors: 1 3 4668047711 14004143133