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140042301547 is a prime number
BaseRepresentation
bin1000001001101100101…
…0111111000001101011
3111101110210022000120011
42002123022333001223
54243301312122142
6144200132312351
713055243631301
oct2023312770153
9441423260504
10140042301547
11544342569a5
1223183a726b7
131028a5832b5
146ac70c0271
1539997ca417
hex209b2bf06b

140042301547 has 2 divisors, whose sum is σ = 140042301548. Its totient is φ = 140042301546.

The previous prime is 140042301523. The next prime is 140042301577. The reversal of 140042301547 is 745103240041.

140042301547 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 140042301547 - 211 = 140042299499 is a prime.

It is a super-2 number, since 2×1400423015472 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (140042301517) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70021150773 + 70021150774.

It is an arithmetic number, because the mean of its divisors is an integer number (70021150774).

Almost surely, 2140042301547 is an apocalyptic number.

140042301547 is a deficient number, since it is larger than the sum of its proper divisors (1).

140042301547 is an equidigital number, since it uses as much as digits as its factorization.

140042301547 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13440, while the sum is 31.

Adding to 140042301547 its reverse (745103240041), we get a palindrome (885145541588).

The spelling of 140042301547 in words is "one hundred forty billion, forty-two million, three hundred one thousand, five hundred forty-seven".