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140042431011251 is a prime number
BaseRepresentation
bin11111110101111000101011…
…010110101001100110110011
3200100211220222210200020121102
4133311320223112221212303
5121323423344314330001
61213502334334515015
741332505663653166
oct3765705326514663
9610756883606542
10140042431011251
1140692730452a9a
12138591b2965a6b
13601ac38318c52
1426821386abadd
15112cc59622e6b
hex7f5e2b5a99b3

140042431011251 has 2 divisors, whose sum is σ = 140042431011252. Its totient is φ = 140042431011250.

The previous prime is 140042431011247. The next prime is 140042431011341. The reversal of 140042431011251 is 152110134240041.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 140042431011251 - 22 = 140042431011247 is a prime.

It is a super-2 number, since 2×1400424310112512 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (140042431211251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70021215505625 + 70021215505626.

It is an arithmetic number, because the mean of its divisors is an integer number (70021215505626).

Almost surely, 2140042431011251 is an apocalyptic number.

140042431011251 is a deficient number, since it is larger than the sum of its proper divisors (1).

140042431011251 is an equidigital number, since it uses as much as digits as its factorization.

140042431011251 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3840, while the sum is 29.

Adding to 140042431011251 its reverse (152110134240041), we get a palindrome (292152565251292).

The spelling of 140042431011251 in words is "one hundred forty trillion, forty-two billion, four hundred thirty-one million, eleven thousand, two hundred fifty-one".