140043034121101 has 4 divisors (see below), whose sum is σ = 140768645697052. Its totient is φ = 139317422545152.

The previous prime is 140043034120981. The next prime is 140043034121117. The reversal of 140043034121101 is 101121430340041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10476582930025 + 129566451191076 = 3236755^2 + 11382726^2 .

It is a cyclic number.

It is not a de Polignac number, because 140043034121101 - 2¹⁷ = 140043033990029 is a prime.

It is a super-2 number, since 2×140043034121101² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140043034121171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 362805787686 + ... + 362805788071.

It is an arithmetic number, because the mean of its divisors is an integer number (35192161424263).

Almost surely, 2^{140043034121101} is an apocalyptic number.

It is an amenable number.

140043034121101 is a deficient number, since it is larger than the sum of its proper divisors (725611575951).

140043034121101 is an equidigital number, since it uses as much as digits as its factorization.

140043034121101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 725611575950.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 140043034121101 its reverse (101121430340041), we get a palindrome (241164464461142).

The spelling of 140043034121101 in words is "one hundred forty trillion, forty-three billion, thirty-four million, one hundred twenty-one thousand, one hundred one".