Search a number
-
+
140044033551 = 3137340739741
BaseRepresentation
bin1000001001101101000…
…1100101111000001111
3111101110220120000102110
42002123101211320033
54243302233033201
6144200233355103
713055264434002
oct2023321457017
9441426500373
10140044033551
115443522a204
1223184568a93
131028aa3b756
146ac7411539
153999a1d6d6
hex209b465e0f

140044033551 has 8 divisors (see below), whose sum is σ = 188088337584. Its totient is φ = 92681209280.

The previous prime is 140044033499. The next prime is 140044033553. The reversal of 140044033551 is 155330440041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 140044033551 - 211 = 140044031503 is a prime.

It is a super-2 number, since 2×1400440335512 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140044033553) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 170369460 + ... + 170370281.

It is an arithmetic number, because the mean of its divisors is an integer number (23511042198).

Almost surely, 2140044033551 is an apocalyptic number.

140044033551 is a deficient number, since it is larger than the sum of its proper divisors (48044304033).

140044033551 is a wasteful number, since it uses less digits than its factorization.

140044033551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 340739881.

The product of its (nonzero) digits is 14400, while the sum is 30.

Adding to 140044033551 its reverse (155330440041), we get a palindrome (295374473592).

The spelling of 140044033551 in words is "one hundred forty billion, forty-four million, thirty-three thousand, five hundred fifty-one".

Divisors: 1 3 137 411 340739741 1022219223 46681344517 140044033551