Base | Representation |
---|---|
bin | 1000001001101101001… |
… | …0010100001101000101 |
3 | 111101110220220122201020 |
4 | 2002123102110031011 |
5 | 4243302310121201 |
6 | 144200241421353 |
7 | 13055266154133 |
oct | 2023322241505 |
9 | 441426818636 |
10 | 140044223301 |
11 | 54435349824 |
12 | 2318463a859 |
13 | 1028aaa6c28 |
14 | 6ac7460753 |
15 | 3999a59a36 |
hex | 209b494345 |
140044223301 has 4 divisors (see below), whose sum is σ = 186725631072. Its totient is φ = 93362815532.
The previous prime is 140044223299. The next prime is 140044223309. The reversal of 140044223301 is 103322440041.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 140044223301 - 21 = 140044223299 is a prime.
It is a super-2 number, since 2×1400442233012 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (140044223309) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23340703881 + ... + 23340703886.
It is an arithmetic number, because the mean of its divisors is an integer number (46681407768).
Almost surely, 2140044223301 is an apocalyptic number.
It is an amenable number.
140044223301 is a deficient number, since it is larger than the sum of its proper divisors (46681407771).
140044223301 is an equidigital number, since it uses as much as digits as its factorization.
140044223301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 46681407770.
The product of its (nonzero) digits is 2304, while the sum is 24.
Adding to 140044223301 its reverse (103322440041), we get a palindrome (243366663342).
The spelling of 140044223301 in words is "one hundred forty billion, forty-four million, two hundred twenty-three thousand, three hundred one".
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