1400496113 has 2 divisors, whose sum is σ = 1400496114. Its totient is φ = 1400496112.

The previous prime is 1400496103. The next prime is 1400496127. The reversal of 1400496113 is 3116940041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 975187984 + 425308129 = 31228^2 + 20623^2 .

It is an emirp because it is prime and its reverse (3116940041) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1400496113 is a prime.

It is a super-2 number, since 2×1400496113² = 3922778725056217538, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1400496103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700248056 + 700248057.

It is an arithmetic number, because the mean of its divisors is an integer number (700248057).

Almost surely, 2^1400496113 is an apocalyptic number.

It is an amenable number.

1400496113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1400496113 is an equidigital number, since it uses as much as digits as its factorization.

1400496113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 29.

The square root of 1400496113 is about 37423.2028693430. The cubic root of 1400496113 is about 1118.8210684106.

The spelling of 1400496113 in words is "one billion, four hundred million, four hundred ninety-six thousand, one hundred thirteen".