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14005010401 is a prime number
BaseRepresentation
bin11010000101100001…
…10111111111100001
31100011000220020112221
431002300313333201
5212140240313101
610233411551041
71004025424054
oct150260677741
940130806487
1014005010401
115a37510668
12286a2bb481
131422674605
1496c01ca9b
1556e7c2aa1
hex342c37fe1

14005010401 has 2 divisors, whose sum is σ = 14005010402. Its totient is φ = 14005010400.

The previous prime is 14005010377. The next prime is 14005010407. The reversal of 14005010401 is 10401050041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13865298001 + 139712400 = 117751^2 + 11820^2 .

It is a cyclic number.

It is not a de Polignac number, because 14005010401 - 27 = 14005010273 is a prime.

It is a super-2 number, since 2×140050104012 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14005010407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7002505200 + 7002505201.

It is an arithmetic number, because the mean of its divisors is an integer number (7002505201).

Almost surely, 214005010401 is an apocalyptic number.

It is an amenable number.

14005010401 is a deficient number, since it is larger than the sum of its proper divisors (1).

14005010401 is an equidigital number, since it uses as much as digits as its factorization.

14005010401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 80, while the sum is 16.

Adding to 14005010401 its reverse (10401050041), we get a palindrome (24406060442).

The spelling of 14005010401 in words is "fourteen billion, five million, ten thousand, four hundred one".