Base | Representation |
---|---|
bin | 11010000101100001… |
… | …11011101011011001 |
3 | 1100011000221000021001 |
4 | 31002300323223121 |
5 | 212140241303442 |
6 | 10233412145001 |
7 | 1004025516061 |
oct | 150260735331 |
9 | 40130830231 |
10 | 14005025497 |
11 | 5a37520a41 |
12 | 286a308161 |
13 | 142267b448 |
14 | 96c0243a1 |
15 | 56e7c72b7 |
hex | 342c3bad9 |
14005025497 has 2 divisors, whose sum is σ = 14005025498. Its totient is φ = 14005025496.
The previous prime is 14005025491. The next prime is 14005025581. The reversal of 14005025497 is 79452050041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13883673241 + 121352256 = 117829^2 + 11016^2 .
It is a cyclic number.
It is not a de Polignac number, because 14005025497 - 223 = 13996636889 is a prime.
It is a super-2 number, since 2×140050254972 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14005025491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7002512748 + 7002512749.
It is an arithmetic number, because the mean of its divisors is an integer number (7002512749).
Almost surely, 214005025497 is an apocalyptic number.
It is an amenable number.
14005025497 is a deficient number, since it is larger than the sum of its proper divisors (1).
14005025497 is an equidigital number, since it uses as much as digits as its factorization.
14005025497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50400, while the sum is 37.
The spelling of 14005025497 in words is "fourteen billion, five million, twenty-five thousand, four hundred ninety-seven".
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