Base | Representation |
---|---|
bin | 1000001001101110110… |
… | …1110110000100100011 |
3 | 111101111102111022000221 |
4 | 2002123231312010203 |
5 | 4243311132034112 |
6 | 144201100223511 |
7 | 13055414411611 |
oct | 2023355660443 |
9 | 441442438027 |
10 | 140051439907 |
11 | 54439428765 |
12 | 23186b3ab97 |
13 | 1028c432902 |
14 | 6ac83bc6b1 |
15 | 399a4d2e07 |
hex | 209bb76123 |
140051439907 has 2 divisors, whose sum is σ = 140051439908. Its totient is φ = 140051439906.
The previous prime is 140051439863. The next prime is 140051440027. The reversal of 140051439907 is 709934150041.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-140051439907 is a prime.
It is a super-2 number, since 2×1400514399072 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (140051439007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70025719953 + 70025719954.
It is an arithmetic number, because the mean of its divisors is an integer number (70025719954).
Almost surely, 2140051439907 is an apocalyptic number.
140051439907 is a deficient number, since it is larger than the sum of its proper divisors (1).
140051439907 is an equidigital number, since it uses as much as digits as its factorization.
140051439907 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 136080, while the sum is 43.
Adding to 140051439907 its reverse (709934150041), we get a palindrome (849985589948).
The spelling of 140051439907 in words is "one hundred forty billion, fifty-one million, four hundred thirty-nine thousand, nine hundred seven".
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