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14008542593 is a prime number
BaseRepresentation
bin11010000101111100…
…10110010110000001
31100011021112200210212
431002332112112001
5212142141330333
610234015403505
71004100435023
oct150276262601
940137480725
1014008542593
115a39503431
12286b523595
131423310276
1496c69c013
1556ec6e448
hex342f96581

14008542593 has 2 divisors, whose sum is σ = 14008542594. Its totient is φ = 14008542592.

The previous prime is 14008542553. The next prime is 14008542617. The reversal of 14008542593 is 39524580041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7795477264 + 6213065329 = 88292^2 + 78823^2 .

It is a cyclic number.

It is not a de Polignac number, because 14008542593 - 214 = 14008526209 is a prime.

It is a super-3 number, since 3×140085425933 (a number of 31 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14008542593.

It is not a weakly prime, because it can be changed into another prime (14008542553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7004271296 + 7004271297.

It is an arithmetic number, because the mean of its divisors is an integer number (7004271297).

Almost surely, 214008542593 is an apocalyptic number.

It is an amenable number.

14008542593 is a deficient number, since it is larger than the sum of its proper divisors (1).

14008542593 is an equidigital number, since it uses as much as digits as its factorization.

14008542593 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 172800, while the sum is 41.

The spelling of 14008542593 in words is "fourteen billion, eight million, five hundred forty-two thousand, five hundred ninety-three".