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14010402111 = 34670134037
BaseRepresentation
bin11010000110001010…
…11100010100111111
31100011102001011120220
431003011130110333
5212143130331421
610234123312423
71004122311246
oct150305342477
940142034526
1014010402111
115a3a563522
12287007b713
131423811784
1496ca2395d
1556eeda3c6
hex34315c53f

14010402111 has 4 divisors (see below), whose sum is σ = 18680536152. Its totient is φ = 9340268072.

The previous prime is 14010402089. The next prime is 14010402143. The reversal of 14010402111 is 11120401041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14010402111 - 26 = 14010402047 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14010402011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2335067016 + ... + 2335067021.

It is an arithmetic number, because the mean of its divisors is an integer number (4670134038).

Almost surely, 214010402111 is an apocalyptic number.

14010402111 is a deficient number, since it is larger than the sum of its proper divisors (4670134041).

14010402111 is an equidigital number, since it uses as much as digits as its factorization.

14010402111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4670134040.

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 14010402111 its reverse (11120401041), we get a palindrome (25130803152).

The spelling of 14010402111 in words is "fourteen billion, ten million, four hundred two thousand, one hundred eleven".

Divisors: 1 3 4670134037 14010402111