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140104032113443 is a prime number
BaseRepresentation
bin11111110110110010000011…
…000100001101001100100011
3200101001210222220000110122211
4133312302003010031030203
5121330431024210112233
61213550523120142551
741340116344461256
oct3766620304151443
9611053886013584
10140104032113443
1140706871694902
1213869124a67a57
1360239a46a6788
1426850dda6109d
15112e6626e15cd
hex7f6c8310d323

140104032113443 has 2 divisors, whose sum is σ = 140104032113444. Its totient is φ = 140104032113442.

The previous prime is 140104032113417. The next prime is 140104032113449. The reversal of 140104032113443 is 344311230401041.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140104032113443 is a prime.

It is not a weakly prime, because it can be changed into another prime (140104032113449) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70052016056721 + 70052016056722.

It is an arithmetic number, because the mean of its divisors is an integer number (70052016056722).

Almost surely, 2140104032113443 is an apocalyptic number.

140104032113443 is a deficient number, since it is larger than the sum of its proper divisors (1).

140104032113443 is an equidigital number, since it uses as much as digits as its factorization.

140104032113443 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 140104032113443 its reverse (344311230401041), we get a palindrome (484415262514484).

The spelling of 140104032113443 in words is "one hundred forty trillion, one hundred four billion, thirty-two million, one hundred thirteen thousand, four hundred forty-three".