1401042211335 has 24 divisors (see below), whose sum is σ = 2615278795584. Its totient is φ = 689743857600.

The previous prime is 1401042211249. The next prime is 1401042211343. The reversal of 1401042211335 is 5331122401041.

1401042211335 is a `hidden beast` number, since 1 + 4 + 0 + 104 + 221 + 1 + 335 = 666.

It is not a de Polignac number, because 1401042211335 - 2¹⁰ = 1401042210311 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1401042211299 and 1401042211308.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1197471391 + ... + 1197472560.

It is an arithmetic number, because the mean of its divisors is an integer number (108969949816).

Almost surely, 2^{1401042211335} is an apocalyptic number.

1401042211335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

1401042211335 is a deficient number, since it is larger than the sum of its proper divisors (1214236584249).

1401042211335 is a wasteful number, since it uses less digits than its factorization.

1401042211335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2394943975 (or 2394943972 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 27.

Adding to 1401042211335 its reverse (5331122401041), we get a palindrome (6732164612376).

The spelling of 1401042211335 in words is "one trillion, four hundred one billion, forty-two million, two hundred eleven thousand, three hundred thirty-five".