Base | Representation |
---|---|
bin | 11111110110110011000011… |
… | …100100100111101001111111 |
3 | 200101001220210022102220012210 |
4 | 133312303003210213221333 |
5 | 121330440233233233010 |
6 | 1213551222340231503 |
7 | 41340155225401413 |
oct | 3766630344475177 |
9 | 611056708386183 |
10 | 140105114352255 |
11 | 40707277578948 |
12 | 1386938739b593 |
13 | 6023b17979080 |
14 | 26851a3698d43 |
15 | 112e6c7719b20 |
hex | 7f6cc3927a7f |
140105114352255 has 32 divisors (see below), whose sum is σ = 241778220203520. Its totient is φ = 68870159568000.
The previous prime is 140105114352227. The next prime is 140105114352293. The reversal of 140105114352255 is 552253411501041.
It is not a de Polignac number, because 140105114352255 - 221 = 140105112255103 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 545006371 + ... + 545263380.
It is an arithmetic number, because the mean of its divisors is an integer number (7555569381360).
Almost surely, 2140105114352255 is an apocalyptic number.
140105114352255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
140105114352255 is a deficient number, since it is larger than the sum of its proper divisors (101673105851265).
140105114352255 is a wasteful number, since it uses less digits than its factorization.
140105114352255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1090270431.
The product of its (nonzero) digits is 120000, while the sum is 39.
Adding to 140105114352255 its reverse (552253411501041), we get a palindrome (692358525853296).
The spelling of 140105114352255 in words is "one hundred forty trillion, one hundred five billion, one hundred fourteen million, three hundred fifty-two thousand, two hundred fifty-five".
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