140110010442041 has 2 divisors, whose sum is σ = 140110010442042. Its totient is φ = 140110010442040.

The previous prime is 140110010442011. The next prime is 140110010442191. The reversal of 140110010442041 is 140244010011041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 139904044234816 + 205966207225 = 11828104^2 + 453835^2 .

It is an emirp because it is prime and its reverse (140244010011041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140110010442041 - 2¹⁴ = 140110010425657 is a prime.

It is a super-3 number, since 3×140110010442041³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 140110010441998 and 140110010442016.

It is not a weakly prime, because it can be changed into another prime (140110010442011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70055005221020 + 70055005221021.

It is an arithmetic number, because the mean of its divisors is an integer number (70055005221021).

Almost surely, 2^{140110010442041} is an apocalyptic number.

It is an amenable number.

140110010442041 is a deficient number, since it is larger than the sum of its proper divisors (1).

140110010442041 is an equidigital number, since it uses as much as digits as its factorization.

140110010442041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 512, while the sum is 23.

Adding to 140110010442041 its reverse (140244010011041), we get a palindrome (280354020453082).

The spelling of 140110010442041 in words is "one hundred forty trillion, one hundred ten billion, ten million, four hundred forty-two thousand, forty-one".