Base | Representation |
---|---|
bin | 1000001001111100111… |
… | …0100111110000000011 |
3 | 111101122112100221012211 |
4 | 2002133032213300003 |
5 | 4243421223114101 |
6 | 144211003202551 |
7 | 13060031304136 |
oct | 2023716476003 |
9 | 441575327184 |
10 | 140110363651 |
11 | 54469713a75 |
12 | 231a2816457 |
13 | 1029b6c3a2b |
14 | 6ad215a21d |
15 | 39a0771c51 |
hex | 209f3a7c03 |
140110363651 has 4 divisors (see below), whose sum is σ = 142753955472. Its totient is φ = 137466771832.
The previous prime is 140110363637. The next prime is 140110363709. The reversal of 140110363651 is 156363011041.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 156363011041 = 218963 ⋅714107.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-140110363651 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (140110363051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1321795831 + ... + 1321795936.
It is an arithmetic number, because the mean of its divisors is an integer number (35688488868).
Almost surely, 2140110363651 is an apocalyptic number.
140110363651 is a deficient number, since it is larger than the sum of its proper divisors (2643591821).
140110363651 is an equidigital number, since it uses as much as digits as its factorization.
140110363651 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2643591820.
The product of its (nonzero) digits is 6480, while the sum is 31.
Adding to 140110363651 its reverse (156363011041), we get a palindrome (296473374692).
The spelling of 140110363651 in words is "one hundred forty billion, one hundred ten million, three hundred sixty-three thousand, six hundred fifty-one".
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