Search a number
-
+
140110363651 = 532643591767
BaseRepresentation
bin1000001001111100111…
…0100111110000000011
3111101122112100221012211
42002133032213300003
54243421223114101
6144211003202551
713060031304136
oct2023716476003
9441575327184
10140110363651
1154469713a75
12231a2816457
131029b6c3a2b
146ad215a21d
1539a0771c51
hex209f3a7c03

140110363651 has 4 divisors (see below), whose sum is σ = 142753955472. Its totient is φ = 137466771832.

The previous prime is 140110363637. The next prime is 140110363709. The reversal of 140110363651 is 156363011041.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 156363011041 = 218963714107.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140110363651 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140110363051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1321795831 + ... + 1321795936.

It is an arithmetic number, because the mean of its divisors is an integer number (35688488868).

Almost surely, 2140110363651 is an apocalyptic number.

140110363651 is a deficient number, since it is larger than the sum of its proper divisors (2643591821).

140110363651 is an equidigital number, since it uses as much as digits as its factorization.

140110363651 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2643591820.

The product of its (nonzero) digits is 6480, while the sum is 31.

Adding to 140110363651 its reverse (156363011041), we get a palindrome (296473374692).

The spelling of 140110363651 in words is "one hundred forty billion, one hundred ten million, three hundred sixty-three thousand, six hundred fifty-one".

Divisors: 1 53 2643591767 140110363651