Search a number
-
+
14011054451 is a prime number
BaseRepresentation
bin11010000110001111…
…11011100101110011
31100011110021022102122
431003013323211303
5212143312220301
610234145304455
71004130666152
oct150307734563
940143238378
1014011054451
115a3a969649
12287033512b
1314239ac684
1496cb53599
155700b881b
hex3431fb973

14011054451 has 2 divisors, whose sum is σ = 14011054452. Its totient is φ = 14011054450.

The previous prime is 14011054397. The next prime is 14011054459. The reversal of 14011054451 is 15445011041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14011054451 - 230 = 12937312627 is a prime.

It is a super-2 number, since 2×140110544512 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14011054451.

It is not a weakly prime, because it can be changed into another prime (14011054459) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005527225 + 7005527226.

It is an arithmetic number, because the mean of its divisors is an integer number (7005527226).

Almost surely, 214011054451 is an apocalyptic number.

14011054451 is a deficient number, since it is larger than the sum of its proper divisors (1).

14011054451 is an equidigital number, since it uses as much as digits as its factorization.

14011054451 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1600, while the sum is 26.

Adding to 14011054451 its reverse (15445011041), we get a palindrome (29456065492).

The spelling of 14011054451 in words is "fourteen billion, eleven million, fifty-four thousand, four hundred fifty-one".