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14011055321 is a prime number
BaseRepresentation
bin11010000110001111…
…11011110011011001
31100011110021100121212
431003013323303121
5212143312232241
610234145312505
71004131001534
oct150307736331
940143240555
1014011055321
115a3a96a26a
122870335735
1314239acba3
1496cb53a1b
155700b8beb
hex3431fbcd9

14011055321 has 2 divisors, whose sum is σ = 14011055322. Its totient is φ = 14011055320.

The previous prime is 14011055299. The next prime is 14011055339. The reversal of 14011055321 is 12355011041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8760024025 + 5251031296 = 93595^2 + 72464^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14011055321 is a prime.

It is not a weakly prime, because it can be changed into another prime (14011055381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005527660 + 7005527661.

It is an arithmetic number, because the mean of its divisors is an integer number (7005527661).

Almost surely, 214011055321 is an apocalyptic number.

It is an amenable number.

14011055321 is a deficient number, since it is larger than the sum of its proper divisors (1).

14011055321 is an equidigital number, since it uses as much as digits as its factorization.

14011055321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 600, while the sum is 23.

Adding to 14011055321 its reverse (12355011041), we get a palindrome (26366066362).

The spelling of 14011055321 in words is "fourteen billion, eleven million, fifty-five thousand, three hundred twenty-one".