140111210003131 has 2 divisors, whose sum is σ = 140111210003132. Its totient is φ = 140111210003130.

The previous prime is 140111210002997. The next prime is 140111210003143. The reversal of 140111210003131 is 131300012111041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 140111210003131 - 2¹³ = 140111209994939 is a prime.

It is a super-4 number, since 4×140111210003131⁴ (a number of 58 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 140111210003099 and 140111210003108.

It is not a weakly prime, because it can be changed into another prime (140111210093131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70055605001565 + 70055605001566.

It is an arithmetic number, because the mean of its divisors is an integer number (70055605001566).

Almost surely, 2^{140111210003131} is an apocalyptic number.

140111210003131 is a deficient number, since it is larger than the sum of its proper divisors (1).

140111210003131 is an equidigital number, since it uses as much as digits as its factorization.

140111210003131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 140111210003131 its reverse (131300012111041), we get a palindrome (271411222114172).

The spelling of 140111210003131 in words is "one hundred forty trillion, one hundred eleven billion, two hundred ten million, three thousand, one hundred thirty-one".