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140111210303 = 401334914331
BaseRepresentation
bin1000001001111101000…
…1110110011100111111
3111101122120221221121022
42002133101312130333
54243421432212203
6144211033254355
713060041431411
oct2023721663477
9441576857538
10140111210303
115446a142089
12231a2b643bb
131029b92c1cc
146ad22da9b1
1539a088ca38
hex209f47673f

140111210303 has 4 divisors (see below), whose sum is σ = 140146128648. Its totient is φ = 140076291960.

The previous prime is 140111210269. The next prime is 140111210321. The reversal of 140111210303 is 303012111041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140111210303 - 210 = 140111209279 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140111210203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17453153 + ... + 17461178.

It is an arithmetic number, because the mean of its divisors is an integer number (35036532162).

Almost surely, 2140111210303 is an apocalyptic number.

140111210303 is a deficient number, since it is larger than the sum of its proper divisors (34918345).

140111210303 is an equidigital number, since it uses as much as digits as its factorization.

140111210303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34918344.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 140111210303 its reverse (303012111041), we get a palindrome (443123321344).

The spelling of 140111210303 in words is "one hundred forty billion, one hundred eleven million, two hundred ten thousand, three hundred three".

Divisors: 1 4013 34914331 140111210303