Base | Representation |
---|---|
bin | 11111110110111000101111… |
… | …110010111001111111101011 |
3 | 200101002111120011201011120012 |
4 | 133312320233302321333223 |
5 | 121331040242100112021 |
6 | 1213554112544522135 |
7 | 41340462525154562 |
oct | 3766705762717753 |
9 | 611074504634505 |
10 | 140111225004011 |
11 | 40709922905a68 |
12 | 1386a5b192034b |
13 | 602457c947a41 |
14 | 26855c306cbd9 |
15 | 112e933e0d35b |
hex | 7f6e2fcb9feb |
140111225004011 has 2 divisors, whose sum is σ = 140111225004012. Its totient is φ = 140111225004010.
The previous prime is 140111225003993. The next prime is 140111225004043. The reversal of 140111225004011 is 110400522111041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 140111225004011 - 230 = 140110151262187 is a prime.
It is not a weakly prime, because it can be changed into another prime (140111225604011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70055612502005 + 70055612502006.
It is an arithmetic number, because the mean of its divisors is an integer number (70055612502006).
Almost surely, 2140111225004011 is an apocalyptic number.
140111225004011 is a deficient number, since it is larger than the sum of its proper divisors (1).
140111225004011 is an equidigital number, since it uses as much as digits as its factorization.
140111225004011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 320, while the sum is 23.
Adding to 140111225004011 its reverse (110400522111041), we get a palindrome (250511747115052).
The spelling of 140111225004011 in words is "one hundred forty trillion, one hundred eleven billion, two hundred twenty-five million, four thousand, eleven".
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