Base | Representation |
---|---|
bin | 11010000110010001… |
… | …00010100011100011 |
3 | 1100011110120102100202 |
4 | 31003020202203203 |
5 | 212143332322201 |
6 | 10234152535415 |
7 | 1004132232362 |
oct | 150310424343 |
9 | 40143512322 |
10 | 14011214051 |
11 | 5a3aa6854a |
12 | 28703b156b |
13 | 1423a37203 |
14 | 96cb957d9 |
15 | 5700eac6b |
hex | 3432228e3 |
14011214051 has 2 divisors, whose sum is σ = 14011214052. Its totient is φ = 14011214050.
The previous prime is 14011214011. The next prime is 14011214059. The reversal of 14011214051 is 15041211041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14011214051 - 230 = 12937472227 is a prime.
It is not a weakly prime, because it can be changed into another prime (14011214059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005607025 + 7005607026.
It is an arithmetic number, because the mean of its divisors is an integer number (7005607026).
Almost surely, 214011214051 is an apocalyptic number.
14011214051 is a deficient number, since it is larger than the sum of its proper divisors (1).
14011214051 is an equidigital number, since it uses as much as digits as its factorization.
14011214051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 160, while the sum is 20.
Adding to 14011214051 its reverse (15041211041), we get a palindrome (29052425092).
The spelling of 14011214051 in words is "fourteen billion, eleven million, two hundred fourteen thousand, fifty-one".
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