Base | Representation |
---|---|
bin | 1100101111100011111100… |
… | …1000001001100001100011 |
3 | 1211121110110120112002011102 |
4 | 3023320333020021201203 |
5 | 3314030011024422243 |
6 | 45444401555105015 |
7 | 2644164435346151 |
oct | 313707710114143 |
9 | 54543416462142 |
10 | 14011242420323 |
11 | 451215308a455 |
12 | 16a35808a216b |
13 | 7a8340168c75 |
14 | 36620d6043d1 |
15 | 1946e7dc59b8 |
hex | cbe3f209863 |
14011242420323 has 2 divisors, whose sum is σ = 14011242420324. Its totient is φ = 14011242420322.
The previous prime is 14011242420313. The next prime is 14011242420389. The reversal of 14011242420323 is 32302424211041.
14011242420323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14011242420323 - 228 = 14010973984867 is a prime.
It is a super-2 number, since 2×140112424203232 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14011242420313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005621210161 + 7005621210162.
It is an arithmetic number, because the mean of its divisors is an integer number (7005621210162).
Almost surely, 214011242420323 is an apocalyptic number.
14011242420323 is a deficient number, since it is larger than the sum of its proper divisors (1).
14011242420323 is an equidigital number, since it uses as much as digits as its factorization.
14011242420323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 14011242420323 its reverse (32302424211041), we get a palindrome (46313666631364).
The spelling of 14011242420323 in words is "fourteen trillion, eleven billion, two hundred forty-two million, four hundred twenty thousand, three hundred twenty-three".
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