Base | Representation |
---|---|
bin | 1100101111100011111100… |
… | …1011010010101001010001 |
3 | 1211121110110122001221012011 |
4 | 3023320333023102221101 |
5 | 3314030011232302423 |
6 | 45444402024502521 |
7 | 2644164445346653 |
oct | 313707713225121 |
9 | 54543418057164 |
10 | 14011243244113 |
11 | 45121535a2375 |
12 | 16a358101aa41 |
13 | 7a8340396c0b |
14 | 36620d77a6d3 |
15 | 1946e7ed9b0d |
hex | cbe3f2d2a51 |
14011243244113 has 2 divisors, whose sum is σ = 14011243244114. Its totient is φ = 14011243244112.
The previous prime is 14011243244029. The next prime is 14011243244123. The reversal of 14011243244113 is 31144234211041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11006682087424 + 3004561156689 = 3317632^2 + 1733367^2 .
It is a cyclic number.
It is not a de Polignac number, because 14011243244113 - 29 = 14011243243601 is a prime.
It is not a weakly prime, because it can be changed into another prime (14011243244123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005621622056 + 7005621622057.
It is an arithmetic number, because the mean of its divisors is an integer number (7005621622057).
Almost surely, 214011243244113 is an apocalyptic number.
It is an amenable number.
14011243244113 is a deficient number, since it is larger than the sum of its proper divisors (1).
14011243244113 is an equidigital number, since it uses as much as digits as its factorization.
14011243244113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 31.
Adding to 14011243244113 its reverse (31144234211041), we get a palindrome (45155477455154).
The spelling of 14011243244113 in words is "fourteen trillion, eleven billion, two hundred forty-three million, two hundred forty-four thousand, one hundred thirteen".
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