14011307 has 2 divisors, whose sum is σ = 14011308. Its totient is φ = 14011306.

The previous prime is 14011297. The next prime is 14011331. The reversal of 14011307 is 70311041.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14011307 - 2⁸ = 14011051 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14011337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005653 + 7005654.

It is an arithmetic number, because the mean of its divisors is an integer number (7005654).

Almost surely, 2^14011307 is an apocalyptic number.

14011307 is a deficient number, since it is larger than the sum of its proper divisors (1).

14011307 is an equidigital number, since it uses as much as digits as its factorization.

14011307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 84, while the sum is 17.

The square root of 14011307 is about 3743.1680432489. The cubic root of 14011307 is about 241.0790934303.

Adding to 14011307 its reverse (70311041), we get a palindrome (84322348).

The spelling of 14011307 in words is "fourteen million, eleven thousand, three hundred seven".