140113114033113 has 96 divisors (see below), whose sum is σ = 237023122976640. Its totient is φ = 82109814151680.

The previous prime is 140113114033051. The next prime is 140113114033127. The reversal of 140113114033113 is 311330411311041.

140113114033113 is a `hidden beast` number, since 1 + 4 + 0 + 1 + 1 + 311 + 4 + 0 + 331 + 13 = 666.

It is not a de Polignac number, because 140113114033113 - 2²⁸ = 140112845597657 is a prime.

It is a super-2 number, since 2×140113114033113² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (140113114033183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3787983 + ... + 17163188.

It is an arithmetic number, because the mean of its divisors is an integer number (2468990864340).

Almost surely, 2^{140113114033113} is an apocalyptic number.

140113114033113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

140113114033113 is a deficient number, since it is larger than the sum of its proper divisors (96910008943527).

140113114033113 is a wasteful number, since it uses less digits than its factorization.

140113114033113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20951301 (or 20951289 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 27.

Adding to 140113114033113 its reverse (311330411311041), we get a palindrome (451443525344154).

The spelling of 140113114033113 in words is "one hundred forty trillion, one hundred thirteen billion, one hundred fourteen million, thirty-three thousand, one hundred thirteen".