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14011331211200 = 2652171927111709
BaseRepresentation
bin1100101111100100010001…
…1010110110111111000000
31211121110200202121010100102
43023321010122312333000
53314030201242224300
645444414450141532
72644166564144531
oct313710432667700
954543622533312
1014011331211200
114512199215344
1216a35a65818a8
137a835568674b
1436621b318688
15194700ab40d5
hexcbe446b6fc0

14011331211200 has 168 divisors, whose sum is σ = 38425968817200. Its totient is φ = 4997230018560.

The previous prime is 14011331211169. The next prime is 14011331211223. The reversal of 14011331211200 is 211213311041.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 13039055 + ... + 14072654.

Almost surely, 214011331211200 is an apocalyptic number.

14011331211200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

14011331211200 is an abundant number, since it is smaller than the sum of its proper divisors (24414637606000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14011331211200 is a wasteful number, since it uses less digits than its factorization.

14011331211200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27111767 (or 27111752 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 14011331211200 its reverse (211213311041), we get a palindrome (14222544522241).

The spelling of 14011331211200 in words is "fourteen trillion, eleven billion, three hundred thirty-one million, two hundred eleven thousand, two hundred".