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14011331224313 is a prime number
BaseRepresentation
bin1100101111100100010001…
…1010111010001011111001
31211121110200202121210100002
43023321010122322023321
53314030201243134223
645444414450322345
72644166564231003
oct313710432721371
954543622553302
1014011331224313
114512199224185
1216a35a65893b5
137a835568c6c7
1436621b31d373
15194700ab7e28
hexcbe446ba2f9

14011331224313 has 2 divisors, whose sum is σ = 14011331224314. Its totient is φ = 14011331224312.

The previous prime is 14011331224223. The next prime is 14011331224349. The reversal of 14011331224313 is 31342213311041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11198908311529 + 2812422912784 = 3346477^2 + 1677028^2 .

It is a cyclic number.

It is not a de Polignac number, because 14011331224313 - 212 = 14011331220217 is a prime.

It is not a weakly prime, because it can be changed into another prime (14011331274313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005665612156 + 7005665612157.

It is an arithmetic number, because the mean of its divisors is an integer number (7005665612157).

Almost surely, 214011331224313 is an apocalyptic number.

It is an amenable number.

14011331224313 is a deficient number, since it is larger than the sum of its proper divisors (1).

14011331224313 is an equidigital number, since it uses as much as digits as its factorization.

14011331224313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 14011331224313 its reverse (31342213311041), we get a palindrome (45353544535354).

The spelling of 14011331224313 in words is "fourteen trillion, eleven billion, three hundred thirty-one million, two hundred twenty-four thousand, three hundred thirteen".