Base | Representation |
---|---|
bin | 1100101111100100010001… |
… | …1010111010001011111001 |
3 | 1211121110200202121210100002 |
4 | 3023321010122322023321 |
5 | 3314030201243134223 |
6 | 45444414450322345 |
7 | 2644166564231003 |
oct | 313710432721371 |
9 | 54543622553302 |
10 | 14011331224313 |
11 | 4512199224185 |
12 | 16a35a65893b5 |
13 | 7a835568c6c7 |
14 | 36621b31d373 |
15 | 194700ab7e28 |
hex | cbe446ba2f9 |
14011331224313 has 2 divisors, whose sum is σ = 14011331224314. Its totient is φ = 14011331224312.
The previous prime is 14011331224223. The next prime is 14011331224349. The reversal of 14011331224313 is 31342213311041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11198908311529 + 2812422912784 = 3346477^2 + 1677028^2 .
It is a cyclic number.
It is not a de Polignac number, because 14011331224313 - 212 = 14011331220217 is a prime.
It is not a weakly prime, because it can be changed into another prime (14011331274313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005665612156 + 7005665612157.
It is an arithmetic number, because the mean of its divisors is an integer number (7005665612157).
Almost surely, 214011331224313 is an apocalyptic number.
It is an amenable number.
14011331224313 is a deficient number, since it is larger than the sum of its proper divisors (1).
14011331224313 is an equidigital number, since it uses as much as digits as its factorization.
14011331224313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 14011331224313 its reverse (31342213311041), we get a palindrome (45353544535354).
The spelling of 14011331224313 in words is "fourteen trillion, eleven billion, three hundred thirty-one million, two hundred twenty-four thousand, three hundred thirteen".
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