Base | Representation |
---|---|
bin | 11010000110010010… |
… | …00010100110011011 |
3 | 1100011110211002102002 |
4 | 31003021002212123 |
5 | 212143401022212 |
6 | 10234155431215 |
7 | 1004133320141 |
oct | 150311024633 |
9 | 40143732362 |
10 | 14011345307 |
11 | 5a40048123 |
12 | 287045550b |
13 | 1423a81b8b |
14 | 96cbcb591 |
15 | 570124ac2 |
hex | 34324299b |
14011345307 has 2 divisors, whose sum is σ = 14011345308. Its totient is φ = 14011345306.
The previous prime is 14011345267. The next prime is 14011345349. The reversal of 14011345307 is 70354311041.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14011345307 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14011345307.
It is not a weakly prime, because it can be changed into another prime (14011342307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005672653 + 7005672654.
It is an arithmetic number, because the mean of its divisors is an integer number (7005672654).
Almost surely, 214011345307 is an apocalyptic number.
14011345307 is a deficient number, since it is larger than the sum of its proper divisors (1).
14011345307 is an equidigital number, since it uses as much as digits as its factorization.
14011345307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5040, while the sum is 29.
Adding to 14011345307 its reverse (70354311041), we get a palindrome (84365656348).
The spelling of 14011345307 in words is "fourteen billion, eleven million, three hundred forty-five thousand, three hundred seven".
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