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14011352969 is a prime number
BaseRepresentation
bin11010000110010010…
…00100011110001001
31100011110211110220212
431003021010132021
5212143401243334
610234155530505
71004133351365
oct150311043611
940143743825
1014011352969
115a40052959
122870459a35
131423a85503
1496cbd02a5
15570126ece
hex343244789

14011352969 has 2 divisors, whose sum is σ = 14011352970. Its totient is φ = 14011352968.

The previous prime is 14011352941. The next prime is 14011353011. The reversal of 14011352969 is 96925311041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8026009744 + 5985343225 = 89588^2 + 77365^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14011352969 is a prime.

It is a super-2 number, since 2×140113529692 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14011352869) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005676484 + 7005676485.

It is an arithmetic number, because the mean of its divisors is an integer number (7005676485).

Almost surely, 214011352969 is an apocalyptic number.

It is an amenable number.

14011352969 is a deficient number, since it is larger than the sum of its proper divisors (1).

14011352969 is an equidigital number, since it uses as much as digits as its factorization.

14011352969 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 58320, while the sum is 41.

The spelling of 14011352969 in words is "fourteen billion, eleven million, three hundred fifty-two thousand, nine hundred sixty-nine".