Base | Representation |
---|---|
bin | 1100101111100100101100… |
… | …0110011110111000101010 |
3 | 1211121110222120112100011100 |
4 | 3023321023012132320222 |
5 | 3314030413441410442 |
6 | 45444433532542230 |
7 | 2644202425030536 |
oct | 313711306367052 |
9 | 54543876470140 |
10 | 14011443310122 |
11 | 451224651a985 |
12 | 16a3618021976 |
13 | 7a837297527b |
14 | 36622c178bc6 |
15 | 19470a85884c |
hex | cbe4b19ee2a |
14011443310122 has 48 divisors (see below), whose sum is σ = 31338293875200. Its totient is φ = 4519694613600.
The previous prime is 14011443310069. The next prime is 14011443310127. The reversal of 14011443310122 is 22101334411041.
It is a happy number.
14011443310122 is a `hidden beast` number, since 14 + 0 + 114 + 433 + 101 + 2 + 2 = 666.
It is not an unprimeable number, because it can be changed into a prime (14011443310127) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 20868504 + ... + 21529452.
It is an arithmetic number, because the mean of its divisors is an integer number (652881122400).
Almost surely, 214011443310122 is an apocalyptic number.
14011443310122 is an abundant number, since it is smaller than the sum of its proper divisors (17326850565078).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14011443310122 is a wasteful number, since it uses less digits than its factorization.
14011443310122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 698979 (or 698976 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 27.
Adding to 14011443310122 its reverse (22101334411041), we get a palindrome (36112777721163).
The spelling of 14011443310122 in words is "fourteen trillion, eleven billion, four hundred forty-three million, three hundred ten thousand, one hundred twenty-two".
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