Base | Representation |
---|---|
bin | 10100011000111100010… |
… | …011101110100110001101 |
3 | 11221221200000201000201111 |
4 | 110120330103232212031 |
5 | 140424044303034203 |
6 | 2551404504212021 |
7 | 203142220130203 |
oct | 24307423564615 |
9 | 4857600630644 |
10 | 1401171143053 |
11 | 4a0262644410 |
12 | 1a768146a011 |
13 | a218c436726 |
14 | 4bb61d87073 |
15 | 266aad9a26d |
hex | 1463c4ee98d |
1401171143053 has 8 divisors (see below), whose sum is σ = 1528587048096. Its totient is φ = 1273761356400.
The previous prime is 1401171143051. The next prime is 1401171143081. The reversal of 1401171143053 is 3503411711041.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1401171143053 - 21 = 1401171143051 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1401171143051) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1044051 + ... + 1972912.
It is an arithmetic number, because the mean of its divisors is an integer number (191073381012).
Almost surely, 21401171143053 is an apocalyptic number.
It is an amenable number.
1401171143053 is a deficient number, since it is larger than the sum of its proper divisors (127415905043).
1401171143053 is a wasteful number, since it uses less digits than its factorization.
1401171143053 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3059195.
The product of its (nonzero) digits is 5040, while the sum is 31.
Adding to 1401171143053 its reverse (3503411711041), we get a palindrome (4904582854094).
The spelling of 1401171143053 in words is "one trillion, four hundred one billion, one hundred seventy-one million, one hundred forty-three thousand, fifty-three".
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