Base | Representation |
---|---|
bin | 101001110000100… |
… | …0110010000000001 |
3 | 10121122120120212011 |
4 | 1103201012100001 |
5 | 10332200412111 |
6 | 351012132521 |
7 | 46502610166 |
oct | 12341062001 |
9 | 3548516764 |
10 | 1401185281 |
11 | 659a29271 |
12 | 331307141 |
13 | 1943a5122 |
14 | d414006d |
15 | 8302b021 |
hex | 53846401 |
1401185281 has 2 divisors, whose sum is σ = 1401185282. Its totient is φ = 1401185280.
The previous prime is 1401185263. The next prime is 1401185321. The reversal of 1401185281 is 1825811041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1356080625 + 45104656 = 36825^2 + 6716^2 .
It is a cyclic number.
It is not a de Polignac number, because 1401185281 - 25 = 1401185249 is a prime.
It is a super-2 number, since 2×14011852812 = 3926640383382097922, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1401185881) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700592640 + 700592641.
It is an arithmetic number, because the mean of its divisors is an integer number (700592641).
Almost surely, 21401185281 is an apocalyptic number.
It is an amenable number.
1401185281 is a deficient number, since it is larger than the sum of its proper divisors (1).
1401185281 is an equidigital number, since it uses as much as digits as its factorization.
1401185281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2560, while the sum is 31.
The square root of 1401185281 is about 37432.4095003247. The cubic root of 1401185281 is about 1119.0045579683.
The spelling of 1401185281 in words is "one billion, four hundred one million, one hundred eighty-five thousand, two hundred eighty-one".
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