Base | Representation |
---|---|
bin | 1100101111100110110110… |
… | …0110110100001101001011 |
3 | 1211121112110220211120102112 |
4 | 3023321231212310031023 |
5 | 3314033110141231103 |
6 | 45445011212452535 |
7 | 2644222654433426 |
oct | 313715546641513 |
9 | 54545426746375 |
10 | 14012022211403 |
11 | 4512513277a97 |
12 | 16a3759a7a14b |
13 | 7a84358945c8 |
14 | 366284dcc9bd |
15 | 1947415a9cd8 |
hex | cbe6d9b434b |
14012022211403 has 2 divisors, whose sum is σ = 14012022211404. Its totient is φ = 14012022211402.
The previous prime is 14012022211381. The next prime is 14012022211471. The reversal of 14012022211403 is 30411222021041.
It is a weak prime.
It is an emirp because it is prime and its reverse (30411222021041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14012022211403 - 216 = 14012022145867 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (14012022111403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006011105701 + 7006011105702.
It is an arithmetic number, because the mean of its divisors is an integer number (7006011105702).
Almost surely, 214012022211403 is an apocalyptic number.
14012022211403 is a deficient number, since it is larger than the sum of its proper divisors (1).
14012022211403 is an equidigital number, since it uses as much as digits as its factorization.
14012022211403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 14012022211403 its reverse (30411222021041), we get a palindrome (44423244232444).
The spelling of 14012022211403 in words is "fourteen trillion, twelve billion, twenty-two million, two hundred eleven thousand, four hundred three".
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